SET BUILDER METHOD –
In this method a set is defined by stating properties which the statement of the set must satisfy. We use braces { } to write set in this form. The brace on the left is followed by a lower-case italic letter that represents any element of the given set. This letter is followed by a vertical bar and the brace on the right. Symbolically, it is of the form {x ǀ -}. Here we write the condition which ‘x’ satisfies, or more briefly, {x ǀ P(x)}, P(x) is a proposition stating a condition for x. The x is a sort of place holder, for all possible elements ‘x’ that have the given property. The vertical line is a symbol for ‘such that’ and the symbolic form A = {x ǀ x is even} reads “A is the set of numbers x such that ‘x’ is even. Sometimes a colon (:) or a semicolon (;) is also used in place of the vertical bar.”
{ x ǀ 7 < x < 15 and x ∈ N }
The set of all elements x such that x has the given properties
Example.1) Write the following sets in the set builder form.
(a) The number 1, 3, 5,……….
Ans.) {x ǀ x is an odd number}
(b) The solution of the equation x²+ 11x + 24 = 0
Ans.) {x : x² + 11x + 24 = 0}
4 5 6 7 8 9
(c) F = { -------, -------, -------, -------, -------, ------ }
7 8 9 10 11 12
We observe that in the given set, the denominator of each fraction is 3 more than the numerator. Hence the set builder form of the set is -
n
F = { x ǀ x = --------, n ∈ N and 4 ≤ x ≤ 9 }
n + 3
(d) {0, 1, 16, 84, 256, 625, 1296}
Ans.) We observe that the elements of the given set are the cubes of the first seven whole numbers. In the set builder form C = {x ǀ x = n⁴, n ∈ W and n ≤ 6}
Your second block of text...