LINEAR SUBTRACTION WITH REGROUPING OF NUMBERS
Q.1) 36 - 24 = ?
Ans.) 36 = 3 Tens + 6 Ones.
24 = 2 Tens + 4 Ones.
Subtract Ones = 6 Ones - 4 Ones = 2 Ones.
Subtract Tens = 3 Tens - 2 Tens = 1 Ten.
So, the number is 1 Ten + 2 Ones = 12
So, 36 - 24 = 12 (Ans.)
Q.2) 32 - 23 = ?
Ans.) We have to subtract, 23 from 32
32 = 3 Tens + 2 Ones.
23 = 2 Tens + 3 Ones.
Subtract Ones = 2 Ones - 3 Ones, but we can observe that 2 is smaller than 3, so this is not possible to subtract a number from a smaller number. Now to subtract we will put 1 before 2 Ones and we will consider as 12 Ones and to balance we will subtract 1 from 3 tens (32) and obtained => 32 = 3 Tens + 2 Ones = 2 Tens + 12 Ones
32 = 2 Tens + 12 Ones.
23 = 2 Tens + 3 Ones.
Now, Subtract Ones = 12 Ones – 3 Ones = 9 Ones
Subtract Tens = 2 Tens - 2 Tens = 0 Ten.
So, the number is 0 Ten + 9 Ones = 09 = 9
32 - 23 = 9 (Ans.)
Q.3) 77 - 49 = ?
Ans.) We have to subtract, 49 from 77
77 = 7 Tens + 7 Ones.
49 = 4 Tens + 9 Ones.
Subtract Ones = 7 Ones - 9 Ones, but we can observe that 7 is smaller than 9, so this is not possible to subtract a number from a smaller number. Now to subtract we will put 1 before 7 Ones and we will consider as 17 Ones and to balance we will subtract 1 from 7 tens (77) and obtained => 77 = 7 Tens + 7 Ones = 6 Tens + 17 Ones
77 = 6 Tens + 17 Ones.
49 = 4 Tens + 9 Ones.
Now, Subtract Ones = 17 Ones – 9 Ones = 8 Ones
Subtract Tens = 6 Tens - 4 Tens = 2 Tens.
So, the number is 2 Tens + 8 Ones = 28
77 - 49 = 28 (Ans.)
Q.4) 51 - 43 = ?
Ans.) We have to subtract, 43 from 51
51 = 5 Tens + 1 One.
43 = 4 Tens + 3 Ones.
Subtract Ones = 1 One - 3 Ones, but we can observe that 1 is smaller than 3, so this is not possible to subtract a number from a smaller number. Now to subtract we will put 1 before 1 Ones and we will consider as 11 Ones and to balance we will subtract 1 from 5 tens (51) and obtained => 51 = 5 Tens + 1 Ones = 4 Tens + 11 Ones
51 = 4 Tens + 11 Ones.
43 = 4 Tens + 3 Ones.
Now, Subtract Ones = 11 Ones – 3 Ones = 8 Ones
Subtract Tens = 4 Tens - 4 Tens = 0 Ten.
So, the number is 0 Ten + 8 Ones = 08 = 8
51 - 43 = 8 (Ans.)
Q.5) 62 - 28 = ?
Ans.) 62 = 6 Tens + 2 Ones.
28 = 2 Tens + 8 Ones.
Subtract Ones = 2 Ones - 8 Ones, but we can observe that 2 is smaller than 8, so this is not possible to subtract a number from a smaller number. Now to subtract we will put 1 before 2 Ones and we will consider as 12 Ones and to balance we will subtract 1 from 6 tens (62) and obtained => 62 = 6 Tens + 2 Ones = 5 Tens + 12 Ones
62 = 5 Tens + 12 Ones.
28 = 2 Tens + 8 Ones.
Now, Subtract Ones = 12 Ones – 8 Ones = 4 Ones
Subtract Tens = 5 Tens - 2 Tens = 3 Tens.
So, the number is 3 Tens + 4 Ones = 34
62 - 28 = 34 (Ans.)