CLASS-3
DIVISION WITH REGROUPING

In this division you can see that, by table of 6 you can’t reach to dividend, i.e 72. Dividend must be divided by divisor separately. So,

Step.1)  Write the dividend and divisor as shown   6 ) 7  2 (

Step.2)  Take the first digit from the left of the Dividend which is 7. From the multiplication table of 6 we can observe that , 1 X 6 = 6 , 2 X 6 = 12 , 3 X 6 = 18,…….. Product 6 only which is 6 < 7 , but next other product like 12 , 18 ,….. all > 7 , so we can’t subtract these number from 7 other than 6. So, write 6 at ‘Tens’ column below 7, write 1 as Quotient at the ‘Tens’ place and then subtract 6 from 7,  7 – 6 = 1, here 1 Tens is the remainder.

Step.3)  Now take next digit 2 of the dividend and write at the right side of 1(remainder) in the ones place and now you have 12 ‘Ones’. Now you have to recall the table of 6 again and you can find that 6 X 2 = 12. Write 2 in the ‘Ones’ place in the Quotient and the product 12  under 12 and subtract. There is '0' Remainder and '12' is Quotient.

                         So, Quotient 12 is the answer.

Q.2)  Find the Answer (Quotient)  324 ÷ 3 =  ?

In this division you can see that, by table of 3 you can’t reach to dividend, i.e 325 at a time. Dividend must be divided by divisor separately. So,

Step.1)  Write the dividend and divisor as shown   3 ) 3  2  4 (

Step.2)  Take the first digit from the left of the Dividend which is 3. From the multiplication table of 3 we can observe that, 1 X 3 = 3 , 2 X 3 = 6 , 3 X 3 = 9,……..Product 3 only which is 3 <= 3 , but next other product like 6 , 9 ,….. all > 3 , so we can’t subtract these number from 3 other than 3. So, write 3 at ‘Hundreds’ column below 3, write 1 as Quotient at the ‘Hundreds’ place and then subtract 3 from 3,  3 – 3 = 0 , here 0 Tens is the remainder.

Step.3)  Now take next digit 2 of the dividend and write at the right side of 0  (remainder) in the Ones place and now you have  2 ‘Tens’ at the ‘Ones’ place. Now you have to recall the table of 3 again and you can find that 3X1= 3, 3X2 = 6,…..we can’t divide 2 by any of the obtained product even 3 itself , so we write 0 in the ‘Tens’ place in the Quotient, now change 2 ‘Tens’ into 20 ‘Ones’ and bring 4 ‘Ones’ down from ‘Dividend’ and add with 20 ‘Ones’ and make a new dividend 24 ‘ Ones’. Now we will recall again table Of 3 and we can find 3 X 8 = 24 , Write 8 in the ‘Ones’ place in the Quotient and the product 24  under 24 and subtract. There is 0 remainder and 108 is the Quotient. 

                    So, Quotient 108 is the answer..

Q. 3)  Find the Answer (Quotient)  210 ÷ 6 =  ?

In this division you can see that, by table of 6 you can’t reach to dividend, i.e 210 at a time. Dividend must be divided by divisor separately. So,

Step.1)  Write the dividend and divisor as shown  6 ) 2  1  0  (

Step.2)  Take the first digit from the left of the Dividend which is 2. From the multiplication table of 6 we can observe that, 1 X 6 = 6 , 2 X 6 = 12 , 3 X 6 = 18,…….. Product 6 and other product also > 2, so in the ‘Hundreds’ place in the quotient is empty or 0 as the dividend 2 ‘Hundreds’ can’t be divided by Divisor 6. We will change 2 ‘Hundreds’ to 20 ‘Tens’. So, we will take 1 ‘Ten’ and 2 ‘Hundreds’/ 20 ‘Tens’ together from dividend and consider it as 21 ‘Tens’, and now recall the table of 6 . Write 18 (obtained from 3 X 6 = 18) , at ‘Tens’ column below 21, write 3 as Quotient at the ‘Tens’ place and then subtract 18 from 21,  21 – 18 = 3 , here 3 Tens is the remainder.

Step.3)  Now take next digit 0 of the dividend and bring down at the right side of 3 (remainder) in the ‘ones’ place to make a new dividend and now you have  30  ‘Ones’. Now you have to recall the table of 6 again and you can find that ……6X4= 24, 6X5 = 30,.…….., so we write 5 in the ‘Ones’ place in the Quotient and the product 30 under 30 and subtract.  There is 0 remainder and 35 is the Quotient.

                                                                                                       So, Quotient 35 is the answer.

Q. 4)  Find the Answer (Quotient)  9232 ÷ 4 =  ?

In this division you can see that, by table of 4 you can’t reach to dividend, i.e 9232 at a time. Dividend must be divided by divisor separately. So,

Step.1)  Write the dividend and devisor as shown   4 ) 9  2  3  2  (

Step.2)  Take the first digit from the left of the Dividend which is 9. From the multiplication table of 4 we can observe that, 1 X 4 = 4 , 2 X 4 = 8 , 3 X 4 = 12,……..Product 8 only which is 8 < 9 , but next other product like 12 , 16 ,….. all > 9 , so we can’t subtract these number from 9 other than 8. So, write 8 at ‘Thousands’ column below 9, write 2 as Quotient at the ‘Thousands’ place and then subtract 8 from 9,  9 – 8 = 1 , here 1 ‘Thousand’ is the remainder.

Step.3)  Now take next digit 2 of the dividend and write at the right side of 1  (remainder) in the Hundreds place and now you have  12 ‘Hundreds’ as dividend. Now we have to recall the table of 4 again and you can find that 4X2= 8, 4X3 = 12,…. . we  will write 3 in the ‘Hundreds’ place of quotient and place the product 12 under 12 and Subtract. There is 0 remainder. 

Step.4) Now we will bring down 3 ‘Tens’, but we can’t divide 3 by 4  because 4 > 3, So, write 0 in the ‘Tens’ place in the quotient and change from 3 ‘Tens’ to 30 ‘Ones’, now bring 2 ‘Ones’ down and add to make new dividend 32 ‘Ones’. We have to recall the table of 4 again and we can find that …..4x7=28 , 4x8 =32, 4 X 9 =36,……… we will write 8 in the ‘Ones’ place of quotient and place the product 32 under 32 and subtract. There is 0 remainder and 2308 is the quotient.

                                                                                                       So, the answer is 2308.

Q. 5)  Find the Answer (Quotient)  50 ÷ 3 =  ?

In this division you can see that, by table of 3 you can’t reach to dividend, i.e 50. Dividend must be divided by divisor separately. So, 

Step.1)  Write the dividend and divisor as shown   3 ) 5  0 (

Step.2)  Take the first digit from the left of the Dividend which is 5. From the multiplication table of 3 we can observe that, 1 X 3 = 3 , 2 X 3 = 6 , 3 X 3 = 9,…….. Product 3 only which is 3 < 5 , but next other product like 6 , 9 ,….. all > 5 , so we can’t subtract these number from 5 other than 3. So, write 3 at ‘Tens’ column below 5, write 1 as Quotient at the ‘Tens’ place and then subtract 3 from 5, 5 – 3 = 2 , here 2 Tens is the remainder. 

Step.3)  Now take next digit 0 of the dividend and write at the right side of 2  (remainder) in the ones place and now you have 20 ‘Ones’. Now you have to recall the table of 3 again like ……3x5=15, 3x6 =18, 3x7 =21, 3x8 =24,…………..and you can place 3 X 6 = 18. But you can’t place 3 x 7 = 21 because 18< 20, But 21 > 20 , so write 6 in the ‘Ones’ place of Quotient and place the product 18  under 20 and subtract. There is 2 remainder and 16 is Quotient.

                                                                                                                                                                                                        So, 16 is the Quotient and 2 is the Remainder.