CLASS-6
FINDING HCF VIA DIVISION METHOD

Step.1) Find H.C.F of any two of the given numbers and then find H.C.F of the third given number and the H.C.F number obtained from the first two numbers.

Step.2) Take two numbers 120 & 576, consider the greater number as ‘Dividend’ and the smaller number as ‘Divisor’, so, consider 576 as ‘Dividend’ and 120 as ‘Divisor’.

Step.3)  Start division like normal division and you will find the remainder every time, and then again we have to divide ‘Divisor’ by ‘Remainder’. Here 96 is ‘Remainder’ and 120 is ‘Divisor’, as per the given communication we will divide 120 by 96 and the steps continue.

Step.4) Continue step 2 until the ‘Remainder’ becomes 0 (Zero). The last ‘Divisor’ is the desired H.C.F, so 24 is the H.C.F of both the numbers 120 & 576.

Step.5) Now, we have to find  H.C.F through the division method of third given number 444 and H.C.F  24  obtained from two given numbers 120 & 576.

 We will consider 24 as ‘Divisor’ and 444 as ‘Dividend

Step.6) we will continue Step.3 & Step.4, process of division method continues till ‘Remainder’ is 0 (Zero)

So, H.C.F of 24 & 444 is 12,

So, H.C.F of given three numbers 120, 576, 444 is 12.     (Ans.)