Area of the Trapezium –
In the figure, WX and ZY are the parallel sides of the trapezium WXYZ. The perpendicular distance between WX & ZY, that is the height of the trapezium is ‘h’
Let, WX = a, and ZY = b
1
Then the area of triangle WXY = ------- X base X height
2
1 1
= ------- X a X h = ------- ah
2 2
1
Area of the triangle WYZ = ------- X base X height
2
1 1
= ------- X b X h = -------- bh
2 2
The area of the trapezium WXYZ = the area of ∆ WXY + the area of ∆ WYZ
1 1
= ------- ah + ------- bh
2 2
1
= ------- (a + b).h
2
So, the area of trapezium = 1 / 2 (sum of its parallel sides) X height